What is expand (pi(-sqrt(3)+2))/(12) ?

The solution to expand (pi(-sqrt(3)+2))/(12) is -pi/(4sqrt(3))+pi/6

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expand (pi(-sqrt(3)+2))/(12)

expand

\frac{π ( - 3 + 2 )}{12}

- \frac{π}{4 3} + \frac{π}{6}

Decimal Notation

0.07014 \dots

Solution steps

\frac{π ( - 3 + 2 )}{12}

Expand

π (- 3 + 2) : - 3 π + 2 π

= \frac{- 3 π + 2 π}{12}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 3 π + 2 π}{12} = - \frac{3 π}{12} + \frac{2 π}{12}

= - \frac{3 π}{12} + \frac{2 π}{12}

\frac{3 π}{12} = \frac{π}{4 3}

\frac{2 π}{12} = \frac{π}{6}

= - \frac{π}{4 3} + \frac{π}{6}

(1 + tan (x))^{3} sec^{2} (x)

(x^{\frac{1}{2}} + 1) (x^{\frac{1}{2}} - 1)

(x - 4) \cdot (x + 2)

\frac{9 x + 25}{( x + 3 ) ^{2}}

\frac{x + 2}{( x + 3 ) ( x - 1 )}

What is expand (pi(-sqrt(3)+2))/(12) ?
The solution to expand (pi(-sqrt(3)+2))/(12) is -pi/(4sqrt(3))+pi/6