What is expand e^x(-e^{-x}x-e^{-x}) ?

The solution to expand e^x(-e^{-x}x-e^{-x}) is -x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand e^x(-e^{-x}x-e^{-x})

expand

e^{x} (- e^{- x} x - e^{- x})

- x - 1

Solution steps

e^{x} (- e^{- x} x - e^{- x})

Apply the distributive law:

a (b - c) = ab - a c

a = e^{x}, b = - e^{- x} x, c = e^{- x}

= e^{x} (- e^{- x} x) - e^{x} e^{- x}

Apply minus-plus rules

+ (- a) = - a

= - e^{x} e^{- x} x - e^{x} e^{- x}

Simplify

- e^{x} e^{- x} x - e^{x} e^{- x} : - x - 1

= - x - 1

\frac{( 6 - 3 x ) ^{2}}{4}

\frac{s - 1}{( s + 2 ) ( s ^{2} + 4 )}

\frac{2 ( x - 1 ) ^{2}}{( x - 2 ) ( x + 1 )}

(1 + i x)^{2}

(2 e^{x^{2}} + x^{2})^{3}

What is expand e^x(-e^{-x}x-e^{-x}) ?
The solution to expand e^x(-e^{-x}x-e^{-x}) is -x-1