What is expand-4(2x+5-3x=35) ?

The solution to expand-4(2x+5-3x=35) is 4x-20=35

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expand-4(2x+5-3x=35)

expand

- 4 (2 x + 5 - 3 x = 35)

4 x - 20 = 35

Solution steps

- 4 (2 x + 5 - 3 x = 35)

= - 4 (2 x + 5 - 3 \cdot 35 = x)

Distribute parentheses

= (- 4) \cdot 2 x + (- 4) \cdot 5 + (- 4) (- 3 x = 35)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

- 4 \cdot 2 x - 4 \cdot 5 + 4 \cdot 3 x = 35

Expand

- 4 \cdot 2 x - 4 \cdot 5 + 4 \cdot 3 x : 4 x - 20

4 x - 20 = 35

(x + 5) (x - 5)

F (0, - 5)

\frac{10 s ^{3} + 20 s + 2}{( s ^{2} + 2 ) ( s ^{2} + 1 )}

\frac{2 ( 1 + 6 )}{5}

3 (2 - 7)