What is expand 6(3e^{3x}cos(2x)-2e^{3x}sin(2x)) ?

The solution to expand 6(3e^{3x}cos(2x)-2e^{3x}sin(2x)) is 18e^{3x}cos(2x)-12e^{3x}sin(2x)

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expand 6(3e^{3x}cos(2x)-2e^{3x}sin(2x))

expand

6 (3 e^{3 x} cos (2 x) - 2 e^{3 x} sin (2 x))

18 e^{3 x} cos (2 x) - 12 e^{3 x} sin (2 x)

Solution steps

6 (3 e^{3 x} cos (2 x) - 2 e^{3 x} sin (2 x))

Apply the distributive law:

a (b - c) = ab - a c

a = 6, b = 3 e^{3 x} cos (2 x), c = 2 e^{3 x} sin (2 x)

= 6 \cdot 3 e^{3 x} cos (2 x) - 6 \cdot 2 e^{3 x} sin (2 x)

Simplify

6 \cdot 3 e^{3 x} cos (2 x) - 6 \cdot 2 e^{3 x} sin (2 x) : 18 e^{3 x} cos (2 x) - 12 e^{3 x} sin (2 x)

= 18 e^{3 x} cos (2 x) - 12 e^{3 x} sin (2 x)

2 - (sin (x) + cos (y)) 2 - (cos (x) + sin (y)) 2

(x + 2 - 3) (x + 2 + 3)

lo g_{10} (7) (5 y (3 y + 4))

\frac{2 ( - x ^{2} - 3 )}{9 ( x ^{2} - 1 ) ^{\frac{5}{3}}}

\frac{( - 2 x ^{2} + 18 )}{( x ^{2} + 9 ) ^{2}}

What is expand 6(3e^{3x}cos(2x)-2e^{3x}sin(2x)) ?
The solution to expand 6(3e^{3x}cos(2x)-2e^{3x}sin(2x)) is 18e^{3x}cos(2x)-12e^{3x}sin(2x)