What is expand ((e^2+1)(e+1)(e-1))/(2e^2) ?

The solution to expand ((e^2+1)(e+1)(e-1))/(2e^2) is (e^2)/2-1/(2e^2)

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expand ((e^2+1)(e+1)(e-1))/(2e^2)

expand

\frac{( e ^{2} + 1 ) ( e + 1 ) ( e - 1 )}{2 e ^{2}}

\frac{e ^{2}}{2} - \frac{1}{2 e ^{2}}

Decimal Notation

3.62686 \dots

Solution steps

\frac{( e ^{2} + 1 ) ( e + 1 ) ( e - 1 )}{2 e ^{2}}

Expand

(e^{2} + 1) (e + 1) (e - 1) : e^{4} - 1

= \frac{e ^{4} - 1}{2 e ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{e ^{4} - 1}{2 e ^{2}} = \frac{e ^{4}}{2 e ^{2}} - \frac{1}{2 e ^{2}}

= \frac{e ^{4}}{2 e ^{2}} - \frac{1}{2 e ^{2}}

Cancel

\frac{e ^{4}}{2 e ^{2}} : \frac{e ^{2}}{2}

= \frac{e ^{2}}{2} - \frac{1}{2 e ^{2}}

\frac{1}{3 ( s + 2 )}

(x - 3)^{2} (x - 7)

t (2 c t + b)

A (2, - 1) C (- 1, 3)

\frac{1}{( x - 7 ) ^{2}}

What is expand ((e^2+1)(e+1)(e-1))/(2e^2) ?
The solution to expand ((e^2+1)(e+1)(e-1))/(2e^2) is (e^2)/2-1/(2e^2)