What is expand sin(2t)*U(t-pi) ?

The solution to expand sin(2t)*U(t-pi) is tUsin(2t)-piUsin(2t)

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expand sin(2t)*U(t-pi)

expand

sin (2 t) \cdot U (t - π)

t U sin (2 t) - π U sin (2 t)

Solution steps

sin (2 t) U (t - π)

= U sin (2 t) (t - π)

Apply the distributive law:

a (b - c) = ab - a c

a = sin (2 t) U, b = t, c = π

= sin (2 t) U t - sin (2 t) U π

= t U sin (2 t) - π U sin (2 t)

(\frac{x ^{2}}{y} - \frac{y ^{\frac{1}{2}}}{x})^{9}

4 (cos (5 x) + cos (3 x)) (sin (3 x) - sin (x))

e^{t} (3 cos (5 t) - 2 sin (5 t))

(x^{2} - 9) (- x)

5 (3 + 2)

What is expand sin(2t)*U(t-pi) ?
The solution to expand sin(2t)*U(t-pi) is tUsin(2t)-piUsin(2t)