What are the solutions to the equation (x+7)(x-5)=13 ?

The solutions to the equation (x+7)(x-5)=13 are x=6,x=-8

Find the zeros of (x+7)(x-5)=13

The zeros of (x+7)(x-5)=13 are x=6,x=-8

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(x + 7) (x - 5) = 13

x = 6, x = - 8

Solution steps

(x + 7) (x - 5) = 13

Expand

(x + 7) (x - 5) : x^{2} + 2 x - 35

x^{2} + 2 x - 35 = 13

Move

13

to the left side

x^{2} + 2 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 48 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 48) = 14

x_{1, 2} = \frac{- 2 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 14}{2 \cdot 1}, x_{2} = \frac{- 2 - 14}{2 \cdot 1}

x = \frac{- 2 + 14}{2 \cdot 1} : 6

x = \frac{- 2 - 14}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 6, x = - 8

\frac{n !}{2 ! ( n - 2 ) !}

- 2 (3) + 3

\frac{w}{2} - 4 = 6

(\frac{3}{2})^{6}

- 18 z \geq - 144

What are the solutions to the equation (x+7)(x-5)=13 ?
The solutions to the equation (x+7)(x-5)=13 are x=6,x=-8
Find the zeros of (x+7)(x-5)=13
The zeros of (x+7)(x-5)=13 are x=6,x=-8