What are the solutions to the equation 2(x+4)^2=40 ?

The solutions to the equation 2(x+4)^2=40 are x=2sqrt(5)-4,x=-2sqrt(5)-4

Find the zeros of 2(x+4)^2=40

The zeros of 2(x+4)^2=40 are x=2sqrt(5)-4,x=-2sqrt(5)-4

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2 (x + 4)^{2} = 40

x = 25 - 4, x = - 25 - 4

Decimal Notation

x = 0.47213 \dots, x = - 8.47213 \dots

Solution steps

2 (x + 4)^{2} = 40

Divide both sides by

2

(x + 4)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 20 : x = 25 - 4

Solve

x + 4 = - 20 : x = - 25 - 4

The solutions to the quadratic equation are:

x = 25 - 4, x = - 25 - 4

25 x^{2} + 16 = 40 x

3 x^{2} - 7 x = 6

\frac{3}{a ^{- 9} b}

(\frac{7}{8})^{- 2}

18 x^{2} - 3 x < 1

What are the solutions to the equation 2(x+4)^2=40 ?
The solutions to the equation 2(x+4)^2=40 are x=2sqrt(5)-4,x=-2sqrt(5)-4
Find the zeros of 2(x+4)^2=40
The zeros of 2(x+4)^2=40 are x=2sqrt(5)-4,x=-2sqrt(5)-4