What is expand ((-x+1)^3)/3 ?

The solution to expand ((-x+1)^3)/3 is -(x^3)/3+x^2-x+1/3

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expand ((-x+1)^3)/3

expand

\frac{( - x + 1 ) ^{3}}{3}

- \frac{x ^{3}}{3} + x^{2} - x + \frac{1}{3}

Solution steps

\frac{( - x + 1 ) ^{3}}{3}

(- x + 1)^{3} = - x^{3} + 3 x^{2} - 3 x + 1

= \frac{( - x ^{3} + 3 x ^{2} - 3 x + 1 )}{3}

Remove parentheses:

(- a) = - a

= \frac{- x ^{3} + 3 x ^{2} - 3 x + 1}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- x ^{3} + 3 x ^{2} - 3 x + 1}{3} = - \frac{x ^{3}}{3} + \frac{3 x ^{2}}{3} - \frac{3 x}{3} + \frac{1}{3}

= - \frac{x ^{3}}{3} + \frac{3 x ^{2}}{3} - \frac{3 x}{3} + \frac{1}{3}

Divide the numbers:

\frac{3}{3} = 1

= - \frac{x ^{3}}{3} + x^{2} - x + \frac{1}{3}

50

\frac{12 ( 3 - 5 )}{5}

\frac{1}{2} + \frac{1}{4} (0.8 - 1)

\frac{( - 4 x y - y ) ( x - 4 x y )}{x ^{2} - 16 x y}

What is expand ((-x+1)^3)/3 ?
The solution to expand ((-x+1)^3)/3 is -(x^3)/3+x^2-x+1/3