What is expand (3,0)y(1,-1) ?

The solution to expand (3,0)y(1,-1) is 1*(3*0,)y,-1*(3*0,)y

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expand (3,0)y(1,-1)

expand

(3, 0) y (1, - 1)

1 \cdot (3 \cdot 0,) y, - 1 \cdot (3 \cdot 0,) y

Solution steps

(3, 0) y (1, - 1)

= (3 \cdot 0,) (1, - 1) y

Apply the distributive law:

a (b - c) = ab - a c

a = (3, 0) y, b = 1,, c = 1

= (3, 0) y \cdot 1, - (3, 0) y \cdot 1

= 1 \cdot (3 \cdot 0,) y, - 1 \cdot (3 \cdot 0,) y

x (2 - x)

\frac{d ^{2}}{d x ^{2}} ((y) (y^{3} + 7 y - x^{3}))

- \frac{1}{s ( 3 s - 3 )}

(e^{i x} + e^{- i x})^{3}

\frac{( s )}{( s - 2 ) ( s - 3 ) ( s - 6 )}

What is expand (3,0)y(1,-1) ?
The solution to expand (3,0)y(1,-1) is 1*(3*0,)y,-1*(3*0,)y