What is expand (pi((16A^2+9)^{3/2}-27))/(72) ?

The solution to expand (pi((16A^2+9)^{3/2}-27))/(72) is (pi(16A^2+9)^{3/2}}{72}-\frac{3pi)/8

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expand (pi((16A^2+9)^{3/2}-27))/(72)

expand

\frac{π ( ( 16 A ^{2} + 9 ) ^{\frac{3}{2}} - 27 )}{72}

\frac{π ( 16 A ^{2} + 9 ) ^{\frac{3}{2}}}{72} - \frac{3 π}{8}

Solution steps

\frac{π ( ( 16 A ^{2} + 9 ) ^{\frac{3}{2}} - 27 )}{72}

Expand

π ((16 A^{2} + 9)^{\frac{3}{2}} - 27) : π (16 A^{2} + 9)^{\frac{3}{2}} - 27 π

= \frac{π ( 16 A ^{2} + 9 ) ^{\frac{3}{2}} - 27 π}{72}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{π ( 16 A ^{2} + 9 ) ^{\frac{3}{2}} - 27 π}{72} = \frac{π ( 16 A ^{2} + 9 ) ^{\frac{3}{2}}}{72} - \frac{27 π}{72}

= \frac{π ( 16 A ^{2} + 9 ) ^{\frac{3}{2}}}{72} - \frac{27 π}{72}

Cancel

\frac{27 π}{72} : \frac{3 π}{8}

= \frac{π ( 16 A ^{2} + 9 ) ^{\frac{3}{2}}}{72} - \frac{3 π}{8}

(- 2 - 3 i)^{7}

(e^{\frac{x}{a}} - e^{- \frac{x}{a}})^{2}

\frac{( 1 + e ^{- 2 s} )}{( 4 s + 1 ) ( 3 s + 1 )}

i s \cdot (i s + 1) \cdot (i s + 3) \cdot (i s + 5)

2 (3 + 11)

What is expand (pi((16A^2+9)^{3/2}-27))/(72) ?
The solution to expand (pi((16A^2+9)^{3/2}-27))/(72) is (pi(16A^2+9)^{3/2}}{72}-\frac{3pi)/8