What is (1+e^{ix})^2 ?

The solution to (1+e^{ix})^2 is (1+cos(x)+isin(x))^2

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simplify (1+e^{ix})^2

simplify

(1 + e^{i x})^{2}

(1 + cos (x) + i sin (x))^{2}

Solution steps

(1 + e^{i x})^{2}

Apply imaginary number rule:

e^{ia} = cos (a) + i sin (a)

= (1 + cos (x) + i sin (x))^{2}

- 2 u sin (t) (t - π)

\frac{( x + 3 ) ( x - 2 )}{x - 3}

arctan (f (5 x^{5} - 1))

x (1 + x)^{2}

\frac{( s ^{2} + 6 s + 9 )}{( s - 1 ) ( s - 2 ) ( s + 4 )}