What is expand (x(x-1)(x+2)^2)/((x+3)(x-4)) ?

The solution to expand (x(x-1)(x+2)^2)/((x+3)(x-4)) is (x^4+3x^3-4x)/(x^2-x-12)

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expand (x(x-1)(x+2)^2)/((x+3)(x-4))

expand

\frac{x ( x - 1 ) ( x + 2 ) ^{2}}{( x + 3 ) ( x - 4 )}

\frac{x ^{4} + 3 x ^{3} - 4 x}{x ^{2} - x - 12}

Solution steps

\frac{x ( x - 1 ) ( x + 2 ) ^{2}}{( x + 3 ) ( x - 4 )}

(x + 2)^{2} = x^{2} + 4 x + 4

= \frac{x ( x - 1 ) ( x ^{2} + 4 x + 4 )}{( x + 3 ) ( x - 4 )}

Expand

(x + 3) (x - 4) : x^{2} - x - 12

= \frac{x ( x - 1 ) ( x ^{2} + 4 x + 4 )}{x ^{2} - x - 12}

Expand

x (x - 1) (x^{2} + 4 x + 4) : x^{4} + 3 x^{3} - 4 x

= \frac{x ^{4} + 3 x ^{3} - 4 x}{x ^{2} - x - 12}

\frac{( 4 x - 1 ) ^{4}}{16}

cos (2 (π - θ))

\frac{1}{2} (u - \frac{1}{2} sin (2 u))

\frac{\frac{d}{d x} ( ( 6 x ^{2} - 3 ) ^{4} )}{( 2 x ^{3} + 8 ) ^{5}}

(1 - sin (x))^{2} + (cos (x))^{2}

What is expand (x(x-1)(x+2)^2)/((x+3)(x-4)) ?
The solution to expand (x(x-1)(x+2)^2)/((x+3)(x-4)) is (x^4+3x^3-4x)/(x^2-x-12)