What is expand-(pi^2)/6 (x-1/2) ?

The solution to expand-(pi^2)/6 (x-1/2) is -(pi^2x)/6+(pi^2)/(12)

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expand-(pi^2)/6 (x-1/2)

expand

- \frac{π ^{2}}{6} (x - \frac{1}{2})

- \frac{π ^{2} x}{6} + \frac{π ^{2}}{12}

Solution steps

- \frac{π ^{2}}{6} (x - \frac{1}{2})

Apply the distributive law:

a (b - c) = ab - a c

a = - \frac{π ^{2}}{6}, b = x, c = \frac{1}{2}

= - \frac{π ^{2}}{6} x - (- \frac{π ^{2}}{6}) \frac{1}{2}

Apply minus-plus rules

- (- a) = a

= - \frac{π ^{2}}{6} x + \frac{1}{2} \cdot \frac{π ^{2}}{6}

Simplify

- \frac{π ^{2}}{6} x + \frac{1}{2} \cdot \frac{π ^{2}}{6} : - \frac{π ^{2} x}{6} + \frac{π ^{2}}{12}

= - \frac{π ^{2} x}{6} + \frac{π ^{2}}{12}

11 sin (2 (t + 13)) - 12

20 (6109 - 83)

\frac{( 2 x - 1 ) ^{3}}{8}

\frac{x ^{2} + y ^{2}}{( x + y ) ( x - y )}

What is expand-(pi^2)/6 (x-1/2) ?
The solution to expand-(pi^2)/6 (x-1/2) is -(pi^2x)/6+(pi^2)/(12)