What is the d/(dt)((s)(tan(t)-t)) ?

The d/(dt)((s)(tan(t)-t)) is stan^2(t)

What is the first d/(dt)((s)(tan(t)-t)) ?

The first d/(dt)((s)(tan(t)-t)) is stan^2(t)

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\frac{d}{d t} ((s) (tan (t) - t))

s tan^{2} (t)

Solution steps

\frac{d}{d t} ((s) (tan (t) - t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= s \frac{d}{d t} (tan (t) - t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= s (\frac{d}{d t} (tan (t)) - \frac{d t}{d t})

\frac{d}{d t} (tan (t)) = sec^{2} (t)

\frac{d t}{d t} = 1

= s (sec^{2} (t) - 1)

Use the Pythagorean identity:

sec^{2} (x) = tan^{2} (x) + 1

sec^{2} (x) - 1 = tan^{2} (x)

= s tan^{2} (t)

(2 - 14) (x - 7)

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(2 - 3 z i)^{2}

P_{1} (10, - 3) P_{2} (14, - 7)

\frac{e ^{- s}}{s ( s ^{2} + 4 )}

What is the d/(dt)((s)(tan(t)-t)) ?
The d/(dt)((s)(tan(t)-t)) is stan^2(t)
What is the first d/(dt)((s)(tan(t)-t)) ?
The first d/(dt)((s)(tan(t)-t)) is stan^2(t)