What is ((3x)/2-y/3)((3x)/2+y/3) ?

The solution to ((3x)/2-y/3)((3x)/2+y/3) is ((9x-2y)(9x+2y))/(36)

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simplify ((3x)/2-y/3)((3x)/2+y/3)

simplify

(\frac{3 x}{2} - \frac{y}{3}) (\frac{3 x}{2} + \frac{y}{3})

\frac{( 9 x - 2 y ) ( 9 x + 2 y )}{36}

Solution steps

(\frac{3 x}{2} - \frac{y}{3}) (\frac{3 x}{2} + \frac{y}{3})

Simplify

\frac{3 x}{2} - \frac{y}{3} : \frac{9 x - 2 y}{6}

= \frac{9 x - 2 y}{6} (\frac{3 x}{2} + \frac{y}{3})

Simplify

\frac{3 x}{2} + \frac{y}{3} : \frac{9 x + 2 y}{6}

= \frac{9 x - 2 y}{6} \cdot \frac{9 x + 2 y}{6}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 9 x - 2 y ) ( 9 x + 2 y )}{6 \cdot 6}

Multiply the numbers:

6 \cdot 6 = 36

= \frac{( 9 x - 2 y ) ( 9 x + 2 y )}{36}

\frac{4}{( x ^{2} - 9 ) ^{2}}

\frac{x ^{2} + x - 2}{( 2 x ^{2} - 1 ) ( x + 1 )}

(x + x)^{2}

(2 x^{\frac{2}{3}} - x)^{2}

(3 lo g_{10} (n) + 5 n^{2}) (lo g_{10} (n + 5) + 8 n)

What is ((3x)/2-y/3)((3x)/2+y/3) ?
The solution to ((3x)/2-y/3)((3x)/2+y/3) is ((9x-2y)(9x+2y))/(36)