What is expand (8x(2x-1))/(3(2x+1)) ?

The solution to expand (8x(2x-1))/(3(2x+1)) is (16x^2-8x)/(6x+3)

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expand (8x(2x-1))/(3(2x+1))

expand

\frac{8 x ( 2 x - 1 )}{3 ( 2 x + 1 )}

\frac{16 x ^{2} - 8 x}{6 x + 3}

Solution steps

\frac{8 x ( 2 x - 1 )}{3 ( 2 x + 1 )}

Expand

3 (2 x + 1) : 6 x + 3

= \frac{8 x ( 2 x - 1 )}{6 x + 3}

Expand

8 x (2 x - 1) : 16 x^{2} - 8 x

= \frac{16 x ^{2} - 8 x}{6 x + 3}

2 y e^{x y} x + (x^{2} + y^{2}) (e^{x y} x y + e^{x y})

(a cos (θ) + b sin (θ)) (a sin (θ) + b cos (θ))

- \frac{e ^{x y^{2}} x y ^{3} - y}{x ( 1 + 2 e ^{x y^{2}} x y ^{2} )}

(3 + 3 cos (θ))^{3}

(2 - x + 2) (2 + x + 2)

What is expand (8x(2x-1))/(3(2x+1)) ?
The solution to expand (8x(2x-1))/(3(2x+1)) is (16x^2-8x)/(6x+3)