What is expand (7x+3)/((x+4)(x-1)) ?

The solution to expand (7x+3)/((x+4)(x-1)) is (7x+3)/(x^2+3x-4)

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expand (7x+3)/((x+4)(x-1))

expand

\frac{7 x + 3}{( x + 4 ) ( x - 1 )}

\frac{7 x + 3}{x ^{2} + 3 x - 4}

Solution steps

\frac{7 x + 3}{( x + 4 ) ( x - 1 )}

Expand

(x + 4) (x - 1) : x^{2} + 3 x - 4

= \frac{7 x + 3}{x ^{2} + 3 x - 4}

(a - b) \frac{a + b}{a - b} - (a + b) \frac{a - b}{a + b} + (2 a - 2 b) \frac{1}{a - b}

(n - 1)!

(b c + d e) (b c - d e)

\frac{( 2 x ^{3} - 4 x ^{2} - 15 x + 5 )}{( x - 1 ) ^{2}}

(8 x^{3} + 3 x + 2)^{5}

What is expand (7x+3)/((x+4)(x-1)) ?
The solution to expand (7x+3)/((x+4)(x-1)) is (7x+3)/(x^2+3x-4)