What is expand ((12-x^2)^2)/9 ?

The solution to expand ((12-x^2)^2)/9 is (x^4)/9-(8x^2)/3+16

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expand ((12-x^2)^2)/9

expand

\frac{( 12 - x ^{2} ) ^{2}}{9}

\frac{x ^{4}}{9} - \frac{8 x ^{2}}{3} + 16

Solution steps

\frac{( 12 - x ^{2} ) ^{2}}{9}

(12 - x^{2})^{2} = 144 - 24 x^{2} + x^{4}

= \frac{144 - 24 x ^{2} + x ^{4}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{144 - 24 x ^{2} + x ^{4}}{9} = \frac{144}{9} - \frac{24 x ^{2}}{9} + \frac{x ^{4}}{9}

= \frac{144}{9} - \frac{24 x ^{2}}{9} + \frac{x ^{4}}{9}

Divide the numbers:

\frac{144}{9} = 16

= 16 - \frac{24 x ^{2}}{9} + \frac{x ^{4}}{9}

Cancel

\frac{24 x ^{2}}{9} : \frac{8 x ^{2}}{3}

= 16 - \frac{8 x ^{2}}{3} + \frac{x ^{4}}{9}

Rewrite in standard form

= \frac{x ^{4}}{9} - \frac{8 x ^{2}}{3} + 16

(1 + \frac{1}{2} x)^{6}

x^{\frac{2}{3}} (5 - 2 x)

(b a x - a b c)^{2}

f oco (4, - 3)

(2 + 3 - 0.4 h)^{2}

What is expand ((12-x^2)^2)/9 ?
The solution to expand ((12-x^2)^2)/9 is (x^4)/9-(8x^2)/3+16