What is expand (pi(2ln(2)-1))/2 ?

The solution to expand (pi(2ln(2)-1))/2 is piln(2)-pi/2

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expand (pi(2ln(2)-1))/2

expand

\frac{π ( 2 ln ( 2 ) - 1 )}{2}

π ln (2) - \frac{π}{2}

Decimal Notation

0.60678 \dots

Solution steps

\frac{π ( 2 ln ( 2 ) - 1 )}{2}

Expand

π (2 ln (2) - 1) : 2 π ln (2) - π

= \frac{2 π ln ( 2 ) - π}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 π ln ( 2 ) - π}{2} = \frac{2 π ln ( 2 )}{2} - \frac{π}{2}

= \frac{2 π ln ( 2 )}{2} - \frac{π}{2}

Divide the numbers:

\frac{2}{2} = 1

= π ln (2) - \frac{π}{2}

e^{(t - a)^{2}} u (t - a)

\frac{π ( 2 ln ( 2 ) - 1 )}{4}

(25 - x i)^{2}

\frac{1}{cos ( x )}

\frac{6 x ^{3} + 18 x ^{2} + 11 x + 2}{x ( 6 x ^{2} + 5 x + 1 )}

What is expand (pi(2ln(2)-1))/2 ?
The solution to expand (pi(2ln(2)-1))/2 is piln(2)-pi/2