What is expand ((x+1)(6x-7))/((x+3)(x-3)(3x+2)) ?

The solution to expand ((x+1)(6x-7))/((x+3)(x-3)(3x+2)) is (6x^2-x-7)/(3x^3+2x^2-27x-18)

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expand ((x+1)(6x-7))/((x+3)(x-3)(3x+2))

expand

\frac{( x + 1 ) ( 6 x - 7 )}{( x + 3 ) ( x - 3 ) ( 3 x + 2 )}

\frac{6 x ^{2} - x - 7}{3 x ^{3} + 2 x ^{2} - 27 x - 18}

Solution steps

\frac{( x + 1 ) ( 6 x - 7 )}{( x + 3 ) ( x - 3 ) ( 3 x + 2 )}

Expand

(x + 3) (x - 3) (3 x + 2) : 3 x^{3} + 2 x^{2} - 27 x - 18

= \frac{( x + 1 ) ( 6 x - 7 )}{3 x ^{3} + 2 x ^{2} - 27 x - 18}

Expand

(x + 1) (6 x - 7) : 6 x^{2} - x - 7

= \frac{6 x ^{2} - x - 7}{3 x ^{3} + 2 x ^{2} - 27 x - 18}

\frac{( x - 2 ) ( x + 3 )}{x + 4}

\frac{1}{( 3 n + 1 ) ^{15}}

(2 - 1 - 4 x^{2})^{2}

\frac{x}{( x + 2 ) ( x + 1 )}

\frac{( 3 x + 2 ) ( x - 2 )}{x - 1}

What is expand ((x+1)(6x-7))/((x+3)(x-3)(3x+2)) ?
The solution to expand ((x+1)(6x-7))/((x+3)(x-3)(3x+2)) is (6x^2-x-7)/(3x^3+2x^2-27x-18)