What is expand derivative of (2x-3x^2)+(y-3)y^2+2 ?

The solution to expand derivative of (2x-3x^2)+(y-3)y^2+2 is derivative of 2x^3-3x^2+y^3-3y^2+2

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expand derivative of (2x-3x^2)+(y-3)y^2+2

expand

\frac{d}{d x} ((2 x - 3) x^{2}) + (y - 3) y^{2} + 2

\frac{d}{d x} (2 x^{3} - 3 x^{2}) + y^{3} - 3 y^{2} + 2

Solution steps

\frac{d}{d x} ((2 x - 3) x^{2}) + (y - 3) y^{2} + 2

= \frac{d}{d x} (x^{2} (2 x - 3)) + (y - 3) y^{2} + 2

Expand

y^{2} (y - 3) : y^{3} - 3 y^{2}

= \frac{d}{d x} ((2 x - 3) x^{2}) + y^{3} - 3 y^{2} + 2

Expand

(2 x - 3) x^{2} : 2 x^{3} - 3 x^{2}

= \frac{d}{d x} (2 x^{3} - 3 x^{2}) + y^{3} - 3 y^{2} + 2

x e^{x} (x + 2)

2 (1 - 5)

e^{x} (cos (y) - sin (y))

\frac{1}{6} (8 ln (2) + \frac{15}{2} ln (3))

What is expand derivative of (2x-3x^2)+(y-3)y^2+2 ?
The solution to expand derivative of (2x-3x^2)+(y-3)y^2+2 is derivative of 2x^3-3x^2+y^3-3y^2+2