What is expand (e^t-e^{-t})(e^t+e^{-t}) ?

The solution to expand (e^t-e^{-t})(e^t+e^{-t}) is e^{2t}-e^{-2t}

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expand (e^t-e^{-t})(e^t+e^{-t})

expand

(e^{t} - e^{- t}) (e^{t} + e^{- t})

e^{2 t} - e^{- 2 t}

Solution steps

(e^{t} - e^{- t}) (e^{t} + e^{- t})

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{t}, b = e^{- t}

= (e^{t})^{2} - (e^{- t})^{2}

Simplify

(e^{t})^{2} - (e^{- t})^{2} : e^{2 t} - e^{- 2 t}

= e^{2 t} - e^{- 2 t}

(5 x + 8 y + 12) l e f t (- 3 x - 4 y + 9)

(2, - 3) y (- 5, 8)

\frac{3 ( x - 5 )}{2}

\frac{d ^{3}}{d x ^{3}} ((y) (3 x^{2} - 5))

What is expand (e^t-e^{-t})(e^t+e^{-t}) ?
The solution to expand (e^t-e^{-t})(e^t+e^{-t}) is e^{2t}-e^{-2t}