What is expand y''(x)-(x+1)y'(x)-y ?

The solution to expand y''(x)-(x+1)y'(x)-y is y''(x)-xy'(x)-y'(x)-y

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expand y''(x)-(x+1)y'(x)-y

expand

y^{''} (x) - (x + 1) y^{'} (x) - y

y'' (x) - x y' (x) - y' (x) - y

Solution steps

y^{''} (x) - (x + 1) y^{'} (x) - y

Expand

- y^{'} (x) (x + 1) : - x y^{'} (x) - y^{'} (x)

= y^{''} (x) - x y^{'} (x) - y^{'} (x) - y

\frac{( 4 x ^{4} - 1 ) ^{2}}{16 x ^{4}}

(a + b)^{2}

(2 + 4 - x)^{2}

\frac{x - 1}{( x + 1 ) ( x + 2 ) ^{2}}

\frac{5 x - 5}{( 5 x + 3 ) ^{2}}

What is expand y''(x)-(x+1)y'(x)-y ?
The solution to expand y''(x)-(x+1)y'(x)-y is y''(x)-xy'(x)-y'(x)-y