What is expand (3x^2+80x-3)/((x^2-1)(x+9)) ?

The solution to expand (3x^2+80x-3)/((x^2-1)(x+9)) is (3x^2+80x-3)/(x^3+9x^2-x-9)

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expand (3x^2+80x-3)/((x^2-1)(x+9))

expand

\frac{3 x ^{2} + 80 x - 3}{( x ^{2} - 1 ) ( x + 9 )}

\frac{3 x ^{2} + 80 x - 3}{x ^{3} + 9 x ^{2} - x - 9}

Solution steps

\frac{3 x ^{2} + 80 x - 3}{( x ^{2} - 1 ) ( x + 9 )}

Expand

(x^{2} - 1) (x + 9) : x^{3} + 9 x^{2} - x - 9

= \frac{3 x ^{2} + 80 x - 3}{x ^{3} + 9 x ^{2} - x - 9}

(2 - 3) cos (x) - 3

(x^{\frac{3}{2}} - 1) (x^{- \frac{1}{2}} + 1)

a (15, - 21) b (- 48, - 39) c (- 29, - 23)

\frac{3 x ^{4} + 5}{( x ^{2} + 1 ) ^{2}}

\frac{a}{( 2 - bi ) ^{2}}

What is expand (3x^2+80x-3)/((x^2-1)(x+9)) ?
The solution to expand (3x^2+80x-3)/((x^2-1)(x+9)) is (3x^2+80x-3)/(x^3+9x^2-x-9)