What is expand P(1,-3)yQ(-5,5) ?

The solution to expand P(1,-3)yQ(-5,5) is 1*(-5*5,)PyQ,-3(-5*5,)PyQ

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand P(1,-3)yQ(-5,5)

expand

P (1, - 3) y Q (- 5, 5)

1 \cdot (- 5 \cdot 5,) P y Q, - 3 (- 5 \cdot 5,) P y Q

Solution steps

P (1, - 3) y Q (- 5, 5)

= (1, - 3) (- 5 \cdot 5,) P y Q

Apply the distributive law:

a (b - c) = ab - a c

a = P y Q (- 5, 5), b = 1,, c = 3

= P y Q (- 5, 5) \cdot 1, - P y Q (- 5, 5) \cdot 3

= 1 \cdot (- 5 \cdot 5,) P y Q, - 3 (- 5 \cdot 5,) P y Q

(x + 2 y) d x + (2 x + y) d y

(1 + sin (x))^{2} + cos^{2} (t)

\frac{2 ( 15 - 15 )}{21}

\frac{6 y - ( - 1 ) ^{y} + 3}{2}

ln (2) (x - 1)

What is expand P(1,-3)yQ(-5,5) ?
The solution to expand P(1,-3)yQ(-5,5) is 1*(-5*5,)PyQ,-3(-5*5,)PyQ