What is expand 7(ln(x^2-4)+(2x^2)/(x^2-4)) ?

The solution to expand 7(ln(x^2-4)+(2x^2)/(x^2-4)) is 7ln(x^2-4)+(14x^2)/(x^2-4)

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expand 7(ln(x^2-4)+(2x^2)/(x^2-4))

expand

7 (ln (x^{2} - 4) + \frac{2 x ^{2}}{x ^{2} - 4})

7 ln (x^{2} - 4) + \frac{14 x ^{2}}{x ^{2} - 4}

Solution steps

7 (ln (x^{2} - 4) + \frac{2 x ^{2}}{x ^{2} - 4})

Apply the distributive law:

a (b + c) = ab + a c

a = 7, b = ln (x^{2} - 4), c = \frac{2 x ^{2}}{x ^{2} - 4}

= 7 ln (x^{2} - 4) + 7 \cdot \frac{2 x ^{2}}{x ^{2} - 4}

7 \cdot \frac{2 x ^{2}}{x ^{2} - 4} = \frac{14 x ^{2}}{x ^{2} - 4}

= 7 ln (x^{2} - 4) + \frac{14 x ^{2}}{x ^{2} - 4}

(x + 6 - x) (x + 6 + x)

- \frac{- y ^{2} + x ^{2}}{2 y ( x ^{4} + y ^{4} + x + 2 x ^{2} y ^{2} )}

(x^{2} - 2 x + 3)^{5}

\frac{( 3 x + 2 )}{( 4 x + 1 ) d x}

(1 - i)^{5}

What is expand 7(ln(x^2-4)+(2x^2)/(x^2-4)) ?
The solution to expand 7(ln(x^2-4)+(2x^2)/(x^2-4)) is 7ln(x^2-4)+(14x^2)/(x^2-4)