What is expand 1/(x^2(16x-y^2)^2) ?

The solution to expand 1/(x^2(16x-y^2)^2) is 1/(256x^4-32x^3y^2+x^2y^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/(x^2(16x-y^2)^2)

expand

\frac{1}{x ^{2} ( 16 x - y ^{2} ) ^{2}}

\frac{1}{256 x ^{4} - 32 x ^{3} y ^{2} + x ^{2} y ^{4}}

Solution steps

\frac{1}{x ^{2} ( 16 x - y ^{2} ) ^{2}}

(16 x - y^{2})^{2} = 256 x^{2} - 32 x y^{2} + y^{4}

= \frac{1}{x ^{2} ( 256 x ^{2} - 32 x y ^{2} + y ^{4} )}

Expand

x^{2} (256 x^{2} - 32 x y^{2} + y^{4}) : 256 x^{4} - 32 x^{3} y^{2} + x^{2} y^{4}

= \frac{1}{256 x ^{4} - 32 x ^{3} y ^{2} + x ^{2} y ^{4}}

7 (7 + z 35)

\frac{2 ( n + 1 ) ( n - 1 )}{n ^{2}}

\frac{5 x ^{3} - 3 x ^{2} + 7 x - 3}{( x ^{2} + 1 ) ^{2}}

\frac{x ^{3} + x ^{2} + 2 x + 6}{( x ^{2} + 1 ) ^{2}}

U (1, 0, - 2) + v (3, 1, - 2)

What is expand 1/(x^2(16x-y^2)^2) ?
The solution to expand 1/(x^2(16x-y^2)^2) is 1/(256x^4-32x^3y^2+x^2y^4)