What is 2x+8<= x+7<= 3x+10 ?

The solution to 2x+8<= x+7<= 3x+10 is -3/2 <= x<=-1

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2x+8<= x+7<= 3x+10

2 x + 8 \leq x + 7 \leq 3 x + 10

- \frac{3}{2} \leq x \leq - 1

Interval Notation

[- \frac{3}{2}, - 1]

Decimal Notation

- 1.5 \leq x \leq - 1

Solution steps

2 x + 8 \leq x + 7 \leq 3 x + 10

a \leq u \leq b

then

a \leq u and u \leq b

2 x + 8 \leq x + 7 and x + 7 \leq 3 x + 10

2 x + 8 \leq x + 7 : x \leq - 1

x + 7 \leq 3 x + 10 : x \geq - \frac{3}{2}

Combine the intervals

x \leq - 1 and x \geq - \frac{3}{2}

Merge Overlapping Intervals

- \frac{3}{2} \leq x \leq - 1

\frac{- 5 b ^{3}}{6} \cdot \frac{3 b ^{2}}{- 10}

\frac{π}{3} \cdot 3

(11 - 3)^{2} + (11 + 3)^{2}

∣ x - 4 ∣ > - 1

\frac{3 x - 2}{x - 1} \geq 0

What is 2x+8<= x+7<= 3x+10 ?
The solution to 2x+8<= x+7<= 3x+10 is -3/2 <= x<=-1