What is expand (2(7*7^{1/2}-3*3^{1/2}))/(9*3^{1/2)} ?

The solution to expand (2(7*7^{1/2}-3*3^{1/2}))/(9*3^{1/2)} is (14*7^{1/2})/(9*3^{1/2)}-2/3

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expand (2(77^{1/2}-33^{1/2}))/(9*3^{1/2)}

expand

\frac{2 ( 7 \cdot 7 ^{\frac{1}{2}} - 3 \cdot 3 ^{\frac{1}{2}} )}{9 \cdot 3 ^{\frac{1}{2}}}

\frac{14 \cdot 7 ^{\frac{1}{2}}}{9 \cdot 3 ^{\frac{1}{2}}} - \frac{2}{3}

Decimal Notation

1.70948 \dots

Solution steps

\frac{2 ( 7 \cdot 7 ^{\frac{1}{2}} - 3 \cdot 3 ^{\frac{1}{2}} )}{9 \cdot 3 ^{\frac{1}{2}}}

Expand

2 (7 \cdot 7^{\frac{1}{2}} - 3 \cdot 3^{\frac{1}{2}}) : 14 \cdot 7^{\frac{1}{2}} - 6 \cdot 3^{\frac{1}{2}}

= \frac{14 \cdot 7 ^{\frac{1}{2}} - 6 \cdot 3 ^{\frac{1}{2}}}{9 \cdot 3 ^{\frac{1}{2}}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{14 \cdot 7 ^{\frac{1}{2}} - 6 \cdot 3 ^{\frac{1}{2}}}{9 \cdot 3 ^{\frac{1}{2}}} = \frac{14 \cdot 7 ^{\frac{1}{2}}}{9 \cdot 3 ^{\frac{1}{2}}} - \frac{6 \cdot 3 ^{\frac{1}{2}}}{9 \cdot 3 ^{\frac{1}{2}}}

= \frac{14 \cdot 7 ^{\frac{1}{2}}}{9 \cdot 3 ^{\frac{1}{2}}} - \frac{6 \cdot 3 ^{\frac{1}{2}}}{9 \cdot 3 ^{\frac{1}{2}}}

\frac{6 \cdot 3 ^{\frac{1}{2}}}{9 \cdot 3 ^{\frac{1}{2}}} = \frac{2}{3}

= \frac{14 \cdot 7 ^{\frac{1}{2}}}{9 \cdot 3 ^{\frac{1}{2}}} - \frac{2}{3}

P (- 1, - 1) y C (3, 5)

(2 + x + 1)^{2}

(3 - 1) + (3 + 1) i

\frac{( 2 s + 1 )}{s ( s + 1 ) ( s ^{2} + 4 s + 6 )}

sin (x) (csc (x) + 1) - 1

What is expand (2(7*7^{1/2}-3*3^{1/2}))/(9*3^{1/2)} ?
The solution to expand (2(7*7^{1/2}-3*3^{1/2}))/(9*3^{1/2)} is (14*7^{1/2})/(9*3^{1/2)}-2/3