What is expand-(2(s+1))/(s^2(s+2)(s-3)) ?

The solution to expand-(2(s+1))/(s^2(s+2)(s-3)) is -(2s+2)/(s^4-s^3-6s^2)

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expand-(2(s+1))/(s^2(s+2)(s-3))

expand

- \frac{2 ( s + 1 )}{s ^{2} ( s + 2 ) ( s - 3 )}

- \frac{2 s + 2}{s ^{4} - s ^{3} - 6 s ^{2}}

Solution steps

- \frac{2 ( s + 1 )}{s ^{2} ( s + 2 ) ( s - 3 )}

Expand

s^{2} (s + 2) (s - 3) : s^{4} - s^{3} - 6 s^{2}

= - \frac{2 ( s + 1 )}{s ^{4} - s ^{3} - 6 s ^{2}}

Expand

2 (s + 1) : 2 s + 2

= - \frac{2 s + 2}{s ^{4} - s ^{3} - 6 s ^{2}}

(1 - x^{\frac{1}{2}})^{2}

\frac{2 ( x + h ) + 3 - 2 x + 3}{h}

\frac{( 1 + x ^{2} ) ^{7}}{x ^{2}}

(x + \frac{1}{2}) (x - \frac{1}{3})

\frac{x ^{3} + 2 x - 1}{x ( x - 1 ) ^{2} ( x + 2 )}

What is expand-(2(s+1))/(s^2(s+2)(s-3)) ?
The solution to expand-(2(s+1))/(s^2(s+2)(s-3)) is -(2s+2)/(s^4-s^3-6s^2)