What is expand (2x)left(2x+7) ?

The solution to expand (2x)left(2x+7) is 4elx^2ft+14elxft

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expand (2x)left(2x+7)

expand

(2 x) l e f t (2 x + 7)

4 e l x^{2} f t + 14 e l x f t

Solution steps

(2 x) l e f t (2 x + 7)

= e l f t (2 x) (2 x + 7)

Apply the distributive law:

a (b + c) = ab + a c

a = (2 x) l e f t, b = 2 x, c = 7

= (2 x) l e f t \cdot 2 x + (2 x) l e f t \cdot 7

= 2 e l x f t (2 x) + 7 e l f t (2 x)

Simplify

2 e l x f t (2 x) + 7 e l f t (2 x) : 4 e l x^{2} f t + 14 e l x f t

= 4 e l x^{2} f t + 14 e l x f t

\frac{11 x + 7}{( 2 x - 1 ) ( x + 2 ) ^{2}}

\frac{- 4 x + 6}{( x - 2 ) ^{2} ( x - 1 ) ^{2}}

(x^{\frac{3}{2}} - 4)^{3}

2 (e^{- 0.4 t} - e^{- 0.6 t})

2 (ln (- 1) + 1)

What is expand (2x)left(2x+7) ?
The solution to expand (2x)left(2x+7) is 4elx^2ft+14elxft