What are the solutions to the equation 3x^2-4x-119=0 ?

The solutions to the equation 3x^2-4x-119=0 are x=7,x=-17/3

Find the zeros of 3x^2-4x-119=0

The zeros of 3x^2-4x-119=0 are x=7,x=-17/3

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3 x^{2} - 4 x - 119 = 0

x = 7, x = - \frac{17}{3}

Solution steps

3 x^{2} - 4 x - 119 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 119 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 119) = 38

x_{1, 2} = \frac{- ( - 4 ) \pm 38}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 38}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 38}{2 \cdot 3}

x = \frac{- ( - 4 ) + 38}{2 \cdot 3} : 7

x = \frac{- ( - 4 ) - 38}{2 \cdot 3} : - \frac{17}{3}

The solutions to the quadratic equation are:

x = 7, x = - \frac{17}{3}

3 x^{2} - 6 x - 2 = 0

\frac{6 b}{2 ( b ) ^{3}}

- 5 v = \frac{10}{7}

\frac{π}{12} + \frac{π}{4}

5 x^{2} - 12 x + 4

What are the solutions to the equation 3x^2-4x-119=0 ?
The solutions to the equation 3x^2-4x-119=0 are x=7,x=-17/3
Find the zeros of 3x^2-4x-119=0
The zeros of 3x^2-4x-119=0 are x=7,x=-17/3