What is expand (x^3-2)/((4x+3)(6x-2)) ?

The solution to expand (x^3-2)/((4x+3)(6x-2)) is (x^3-2)/(24x^2+10x-6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x^3-2)/((4x+3)(6x-2))

expand

\frac{x ^{3} - 2}{( 4 x + 3 ) ( 6 x - 2 )}

\frac{x ^{3} - 2}{24 x ^{2} + 10 x - 6}

Solution steps

\frac{x ^{3} - 2}{( 4 x + 3 ) ( 6 x - 2 )}

Expand

(4 x + 3) (6 x - 2) : 24 x^{2} + 10 x - 6

= \frac{x ^{3} - 2}{24 x ^{2} + 10 x - 6}

(1 - x)^{4}

(x^{2} + 7 - 4) (x^{2} + 7 + 4)

(8 - 2 ln (x)) x

\frac{1}{( s ^{2} + 3 s + 2 ) ( s + 4 )}

(\frac{6}{x - 6} + 2 (100 - x)) (x - 6)

What is expand (x^3-2)/((4x+3)(6x-2)) ?
The solution to expand (x^3-2)/((4x+3)(6x-2)) is (x^3-2)/(24x^2+10x-6)