What is expand (x+2)*e^{x-1} ?

The solution to expand (x+2)*e^{x-1} is e^{x-1}x+2e^{x-1}

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expand (x+2)*e^{x-1}

expand

(x + 2) \cdot e^{x - 1}

e^{x - 1} x + 2 e^{x - 1}

Solution steps

(x + 2) e^{x - 1}

= e^{x - 1} (x + 2)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{x - 1}, b = x, c = 2

= e^{x - 1} x + e^{x - 1} \cdot 2

= e^{x - 1} x + 2 e^{x - 1}

\frac{6 s + 7}{( s ^{2} + 6 s + 25 ) ^{2}}

(x + 2) (x + 3) (x - 3)

(sec (x) - tan (x)) (csc (x) - 1)

\frac{d}{d t} ((x) (e^{t} - t))

(2, 5) y (- 1, - 3)

What is expand (x+2)*e^{x-1} ?
The solution to expand (x+2)*e^{x-1} is e^{x-1}x+2e^{x-1}