What are the solutions to the equation x^2+16=8x ?

The solutions to the equation x^2+16=8x are x=4

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x^2+16=8x

x^{2} + 16 = 8 x

x = 4

Solution steps

x^{2} + 16 = 8 x

Move

8 x

to the left side

x^{2} + 16 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

x = 4

The solution to the quadratic equation is:

x = 4

- 30 < - 4 x

9 x^{2} - 12 x + 4 = 0

(\frac{x ^{2}}{x - 5}) \geq 0

1 \cdot \frac{1}{2}

a^{2} - 12 a + 32

What are the solutions to the equation x^2+16=8x ?
The solutions to the equation x^2+16=8x are x=4
Find the zeros of x^2+16=8x
The zeros of x^2+16=8x are x=4