What is expand (2x+3/x)^4 ?

The solution to expand (2x+3/x)^4 is 16x^4+96x^2+216+(216)/(x^2)+(81)/(x^4)

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expand (2x+3/x)^4

expand

(2 x + \frac{3}{x})^{4}

16 x^{4} + 96 x^{2} + 216 + \frac{216}{x ^{2}} + \frac{81}{x ^{4}}

Solution steps

(2 x + \frac{3}{x})^{4}

Apply binomial theorem:

(a + b)^{n} = i = 0 \sum n (i n) a^{(n - i)} b^{i}

a = 2 x, b = \frac{3}{x}

= i = 0 \sum 4 (i 4) (2 x)^{(4 - i)} (\frac{3}{x})^{i}

Expand summation

= \frac{4 !}{0 ! ( 4 - 0 ) !} (2 x)^{4} (\frac{3}{x})^{0} + \frac{4 !}{1 ! ( 4 - 1 ) !} (2 x)^{3} (\frac{3}{x})^{1} + \frac{4 !}{2 ! ( 4 - 2 ) !} (2 x)^{2} (\frac{3}{x})^{2} + \frac{4 !}{3 ! ( 4 - 3 ) !} (2 x)^{1} (\frac{3}{x})^{3} + \frac{4 !}{4 ! ( 4 - 4 ) !} (2 x)^{0} (\frac{3}{x})^{4}

Simplify

\frac{4 !}{0 ! ( 4 - 0 ) !} (2 x)^{4} (\frac{3}{x})^{0} : 16 x^{4}

Simplify

\frac{4 !}{1 ! ( 4 - 1 ) !} (2 x)^{3} (\frac{3}{x})^{1} : 96 x^{2}

Simplify

\frac{4 !}{2 ! ( 4 - 2 ) !} (2 x)^{2} (\frac{3}{x})^{2} : 216

Simplify

\frac{4 !}{3 ! ( 4 - 3 ) !} (2 x)^{1} (\frac{3}{x})^{3} : \frac{216}{x ^{2}}

Simplify

\frac{4 !}{4 ! ( 4 - 4 ) !} (2 x)^{0} (\frac{3}{x})^{4} : \frac{81}{x ^{4}}

= 16 x^{4} + 96 x^{2} + 216 + \frac{216}{x ^{2}} + \frac{81}{x ^{4}}

(2 t + 1) e^{t}

(x + i) (x - i)

\frac{2 ( 8 - 19 )}{3}

f (s) = \frac{6}{( s ^{2} - 4 s + 4 ) ( s - 2 ) ^{4}}

x^{0.1} (1 - e^{20 (x - 1)})

What is expand (2x+3/x)^4 ?
The solution to expand (2x+3/x)^4 is 16x^4+96x^2+216+(216)/(x^2)+(81)/(x^4)