What is expand (4x(x^2-28x-196)(7+x))/(147) ?

The solution to expand (4x(x^2-28x-196)(7+x))/(147) is (4x^4}{147}-\frac{4x^3)/7-(32x^2)/3-(112x)/3

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expand (4x(x^2-28x-196)(7+x))/(147)

expand

\frac{4 x ( x ^{2} - 28 x - 196 ) ( 7 + x )}{147}

\frac{4 x ^{4}}{147} - \frac{4 x ^{3}}{7} - \frac{32 x ^{2}}{3} - \frac{112 x}{3}

Solution steps

\frac{4 x ( x ^{2} - 28 x - 196 ) ( 7 + x )}{147}

Expand

4 x (x^{2} - 28 x - 196) (7 + x) : 4 x^{4} - 84 x^{3} - 1568 x^{2} - 5488 x

= \frac{4 x ^{4} - 84 x ^{3} - 1568 x ^{2} - 5488 x}{147}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{4} - 84 x ^{3} - 1568 x ^{2} - 5488 x}{147} = \frac{4 x ^{4}}{147} - \frac{84 x ^{3}}{147} - \frac{1568 x ^{2}}{147} - \frac{5488 x}{147}

= \frac{4 x ^{4}}{147} - \frac{84 x ^{3}}{147} - \frac{1568 x ^{2}}{147} - \frac{5488 x}{147}

Cancel

\frac{84 x ^{3}}{147} : \frac{4 x ^{3}}{7}

= \frac{4 x ^{4}}{147} - \frac{4 x ^{3}}{7} - \frac{1568 x ^{2}}{147} - \frac{5488 x}{147}

Cancel

\frac{1568 x ^{2}}{147} : \frac{32 x ^{2}}{3}

= \frac{4 x ^{4}}{147} - \frac{4 x ^{3}}{7} - \frac{32 x ^{2}}{3} - \frac{5488 x}{147}

Cancel

\frac{5488 x}{147} : \frac{112 x}{3}

= \frac{4 x ^{4}}{147} - \frac{4 x ^{3}}{7} - \frac{32 x ^{2}}{3} - \frac{112 x}{3}

(1 - cos (x) - sin (x))^{2}

\frac{x ^{2}}{( x - 1 ) ( x + 1 )}

\frac{x - 4}{2 ( x + 4 )}

\frac{e ^{- 2 s}}{s ( s ^{2} + 2 s + 4 )}

(3 x^{3} - x)^{2}

What is expand (4x(x^2-28x-196)(7+x))/(147) ?
The solution to expand (4x(x^2-28x-196)(7+x))/(147) is (4x^4}{147}-\frac{4x^3)/7-(32x^2)/3-(112x)/3