What is expand (4x+4Δx-5)(7x+9) ?

The solution to expand (4x+4Δx-5)(7x+9) is 28Δx^2+28x^2+36Δx+x-45

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4x+4Δx-5)(7x+9)

expand

(4 x + 4Δ x - 5) (7 x + 9)

28Δ x^{2} + 28 x^{2} + 36Δ x + x - 45

Solution steps

(4 x + 4Δ x - 5) (7 x + 9)

Distribute parentheses

= 4 x \cdot 7 x + 4 x \cdot 9 + 4Δ x \cdot 7 x + 4Δ x \cdot 9 + (- 5) \cdot 7 x + (- 5) \cdot 9

Apply minus-plus rules

+ (- a) = - a

= 4 \cdot 7 xx + 4 \cdot 9 x + 4 \cdot 7Δ xx + 4 \cdot 9Δ x - 5 \cdot 7 x - 5 \cdot 9

Simplify

4 \cdot 7 xx + 4 \cdot 9 x + 4 \cdot 7Δ xx + 4 \cdot 9Δ x - 5 \cdot 7 x - 5 \cdot 9 : 28Δ x^{2} + 28 x^{2} + 36Δ x + x - 45

= 28Δ x^{2} + 28 x^{2} + 36Δ x + x - 45

(\frac{n ^{2}}{5} + 4) (\frac{2 n ^{2}}{3} - 7)

\frac{3 x}{( x - 2 ) ^{2}}

(2 - x)^{2}

(1 + cot (β))^{2}

What is expand (4x+4Δx-5)(7x+9) ?
The solution to expand (4x+4Δx-5)(7x+9) is 28Δx^2+28x^2+36Δx+x-45