What is expand (3x+23)/((x-4)(x+1)) ?

The solution to expand (3x+23)/((x-4)(x+1)) is (3x+23)/(x^2-3x-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (3x+23)/((x-4)(x+1))

expand

\frac{3 x + 23}{( x - 4 ) ( x + 1 )}

\frac{3 x + 23}{x ^{2} - 3 x - 4}

Solution steps

\frac{3 x + 23}{( x - 4 ) ( x + 1 )}

Expand

(x - 4) (x + 1) : x^{2} - 3 x - 4

= \frac{3 x + 23}{x ^{2} - 3 x - 4}

A (3, 3) B (6, 6) C (10, - 4)

\frac{2 s ^{2} + 2 s + 6}{s ( s + 1 ) ( s + 3 )}

(x + \frac{5}{6}) (x - \frac{7}{6})

(x - 2) l e f t (x + 3)

(r - \frac{1}{r}) sin (θ)

What is expand (3x+23)/((x-4)(x+1)) ?
The solution to expand (3x+23)/((x-4)(x+1)) is (3x+23)/(x^2-3x-4)