What is expand (x+Δx-1)(x-1) ?

The solution to expand (x+Δx-1)(x-1) is Δx^2-Δx+x^2-2x+1

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expand (x+Δx-1)(x-1)

expand

(x + Δ x - 1) (x - 1)

Δ x^{2} - Δ x + x^{2} - 2 x + 1

Solution steps

(x + Δ x - 1) (x - 1)

Distribute parentheses

= xx + x (- 1) + Δ xx + Δ x (- 1) + (- 1) x + (- 1) (- 1)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= xx - 1 \cdot x + Δ xx - 1Δ x - 1 \cdot x + 1 \cdot 1

Simplify

xx - 1 \cdot x + Δ xx - 1Δ x - 1 \cdot x + 1 \cdot 1 : Δ x^{2} - Δ x + x^{2} - 2 x + 1

= Δ x^{2} - Δ x + x^{2} - 2 x + 1

\frac{( x - 4 ) ^{2}}{2}

(x - \frac{1}{2}) (x + 3)

A (3, 3) B (- 4, - 4)

(y - a) (y - 3 z + 2 a) (y + 3 z + 2 a)

x (x - 4) (x + \frac{1}{2})

What is expand (x+Δx-1)(x-1) ?
The solution to expand (x+Δx-1)(x-1) is Δx^2-Δx+x^2-2x+1