What is expand (x=-1,-5i)(y=5-i) ?

The solution to expand (x=-1,-5i)(y=5-i) is x=0

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expand (x=-1,-5i)(y=5-i)

expand

(x = - 1, - 5 i) (y = 5 - i)

x = 0

Solution steps

(x = - 1, - 5 i) (y = 5 - i)

= (= x - 1, - 5 i) (5 = y - i)

Distribute parentheses

x = y = 5 + x = (- i) + (- 1,) y = 5 + (- 1,) (- i) + (- 5 i) y = 5 + (- 5 i) (- i)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

x = y = 5 - x = i - 1, y = 5 + 1, i - 5 i y = 5 + 5 ii

Expand

5 + 5 ii : 0

x = 0

(2 x + 1)^{2}

(x^{2} - y^{2}) d x + (x^{2} - 2 x y) d y

(2 + 3)^{4}

e^{x} (x - 10)

3 (4 - 35)

What is expand (x=-1,-5i)(y=5-i) ?
The solution to expand (x=-1,-5i)(y=5-i) is x=0