What is expand (240)/((s+1)(s+2)(s+3)(s+4)) ?

The solution to expand (240)/((s+1)(s+2)(s+3)(s+4)) is (240)/(s^4+10s^3+35s^2+50s+24)

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expand (240)/((s+1)(s+2)(s+3)(s+4))

expand

\frac{240}{( s + 1 ) ( s + 2 ) ( s + 3 ) ( s + 4 )}

\frac{240}{s ^{4} + 10 s ^{3} + 35 s ^{2} + 50 s + 24}

Solution steps

\frac{240}{( s + 1 ) ( s + 2 ) ( s + 3 ) ( s + 4 )}

Expand

(s + 1) (s + 2) (s + 3) (s + 4) : s^{4} + 10 s^{3} + 35 s^{2} + 50 s + 24

= \frac{240}{s ^{4} + 10 s ^{3} + 35 s ^{2} + 50 s + 24}

(3 x + 2 y^{2}) d x + 2 x y d y

\frac{( x + 2 ) ( x + 5 )}{x ^{2} + 4 x + 3}

15 (\frac{1}{56250000} - \frac{1}{225000000})

((\frac{9}{x - 4}) + 3 (100 - x)) (x - 4)

(a - b) \cdot (a + b)

What is expand (240)/((s+1)(s+2)(s+3)(s+4)) ?
The solution to expand (240)/((s+1)(s+2)(s+3)(s+4)) is (240)/(s^4+10s^3+35s^2+50s+24)