What is (1+1/x)(1-1/x) ?

The solution to (1+1/x)(1-1/x) is ((x+1)(x-1))/(x^2)

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simplify (1+1/x)(1-1/x)

simplify

(1 + \frac{1}{x}) (1 - \frac{1}{x})

\frac{( x + 1 ) ( x - 1 )}{x ^{2}}

Solution steps

(1 + \frac{1}{x}) (1 - \frac{1}{x})

Join

1 + \frac{1}{x} : \frac{x + 1}{x}

= \frac{x + 1}{x} (1 - \frac{1}{x})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x + 1 ) ( 1 - \frac{1}{x} )}{x}

Simplify

(x + 1) (1 - \frac{1}{x}) : \frac{( x + 1 ) ( x - 1 )}{x}

= \frac{\frac{( x + 1 ) ( x - 1 )}{x}}{x}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( x + 1 ) ( x - 1 )}{xx}

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= \frac{( x + 1 ) ( x - 1 )}{x ^{2}}

\frac{1}{8} y (6 - x - 3 y)^{2}

- \frac{4}{s ( s ^{2} - 6 s )}

2 (11 - 8)

\frac{x + 7}{( x + 6 ) ^{2}}

\frac{1}{4} (\frac{4}{y} + 4 y)