What is (e^{it}+5)^2 ?

The solution to (e^{it}+5)^2 is (cos(t)+isin(t)+5)^2

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simplify (e^{it}+5)^2

simplify

(e^{i t} + 5)^{2}

(cos (t) + i sin (t) + 5)^{2}

Solution steps

(e^{i t} + 5)^{2}

Apply imaginary number rule:

e^{ia} = cos (a) + i sin (a)

= (cos (t) + i sin (t) + 5)^{2}

(x + 3) 5 x^{3} + 2 x^{2} - 45 x - 18

(3 + y - 1)^{2}

(1 - k) - 1

\frac{k ^{2} - a - 6}{( k ^{2} + 2 k ) ( k - 3 )}

\frac{4 x ^{2} + 23 x - 15}{x ( x ^{2} - 2 x - 15 )}