What is expand ((3-x)^2)/2 ?

The solution to expand ((3-x)^2)/2 is (x^2)/2-3x+9/2

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expand ((3-x)^2)/2

expand

\frac{( 3 - x ) ^{2}}{2}

\frac{x ^{2}}{2} - 3 x + \frac{9}{2}

Solution steps

\frac{( 3 - x ) ^{2}}{2}

(3 - x)^{2} = 9 - 6 x + x^{2}

= \frac{9 - 6 x + x ^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 - 6 x + x ^{2}}{2} = \frac{9}{2} - \frac{6 x}{2} + \frac{x ^{2}}{2}

= \frac{9}{2} - \frac{6 x}{2} + \frac{x ^{2}}{2}

Divide the numbers:

\frac{6}{2} = 3

= \frac{9}{2} - 3 x + \frac{x ^{2}}{2}

Rewrite in standard form

= \frac{x ^{2}}{2} - 3 x + \frac{9}{2}

(2, - 3) y (5, 4)

\frac{3 e ^{x}}{( 3 + e ^{x} ) ^{2}}

(sin (x) + x cos (x)) (6 cos (x sin (x)) + 8)

\frac{20 x ^{2} ( 40 x - 759 )}{( 20 x - 253 ) ^{2}}

\frac{x - 5}{( x + 1 ) ( x - 3 )}

What is expand ((3-x)^2)/2 ?
The solution to expand ((3-x)^2)/2 is (x^2)/2-3x+9/2