What is (\partial)/(\partial t)((z)(s^2t-st^{27})) ?

The answer to (\partial)/(\partial t)((z)(s^2t-st^{27})) is z(s^2-27st^{26})

Popular >

(\partial)/(\partial t)((z)(s^2t-st^{27}))

\frac{\partial}{\partial t} ((z) (s^{2} t - s t^{27}))

z (s^{2} - 27 s t^{26})

Solution steps

\frac{\partial}{\partial t} ((z) (s^{2} t - s t^{27}))

Treat

z, s

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{\partial}{\partial t} (s^{2} t - s t^{27})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{\partial}{\partial t} (s^{2} t) - \frac{\partial}{\partial t} (s t^{27}))

\frac{\partial}{\partial t} (s^{2} t) = s^{2}

\frac{\partial}{\partial t} (s t^{27}) = 27 s t^{26}

= z (s^{2} - 27 s t^{26})

(1 + cos (2 x))^{2}

(a + 1 + x) l e f t (a + 1 - x)

\frac{1}{2} (x - 1)^{2}

\frac{d ^{2}}{d x ^{2}} ((y) (y^{3} - x y))

(5 e^{5 t} - e^{- t}) \cdot (25 e^{5 t} + e^{- t})

What is (\partial)/(\partial t)((z)(s^2t-st^{27})) ?
The answer to (\partial)/(\partial t)((z)(s^2t-st^{27})) is z(s^2-27st^{26})