What is expand (2x^{1/4}+5)(2x^{1/4}-5) ?

The solution to expand (2x^{1/4}+5)(2x^{1/4}-5) is 4x^{1/2}-25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x^{1/4}+5)(2x^{1/4}-5)

expand

(2 x^{\frac{1}{4}} + 5) (2 x^{\frac{1}{4}} - 5)

4 x^{\frac{1}{2}} - 25

Solution steps

(2 x^{\frac{1}{4}} + 5) (2 x^{\frac{1}{4}} - 5)

Apply Difference of Two Squares

(2 x^{\frac{1}{4}} + 5) (2 x^{\frac{1}{4}} - 5) : 4 x^{\frac{1}{2}} - 25

= 4 x^{\frac{1}{2}} - 25

x (10 - x)

3 (1 + \frac{4 i}{n})^{2}

(9 + 2) (4 + 7)

sin (a) \cdot (1 + tan (a)) + cos (a) \cdot (1 + cot (a))

(1 - cos (4 x))^{4}

What is expand (2x^{1/4}+5)(2x^{1/4}-5) ?
The solution to expand (2x^{1/4}+5)(2x^{1/4}-5) is 4x^{1/2}-25