What is expand ((x-2)(x-4))/3 ?

The solution to expand ((x-2)(x-4))/3 is (x^2)/3-2x+8/3

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expand ((x-2)(x-4))/3

expand

\frac{( x - 2 ) ( x - 4 )}{3}

\frac{x ^{2}}{3} - 2 x + \frac{8}{3}

Solution steps

\frac{( x - 2 ) ( x - 4 )}{3}

Expand

(x - 2) (x - 4) : x^{2} - 6 x + 8

= \frac{x ^{2} - 6 x + 8}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 6 x + 8}{3} = \frac{x ^{2}}{3} - \frac{6 x}{3} + \frac{8}{3}

= \frac{x ^{2}}{3} - \frac{6 x}{3} + \frac{8}{3}

Divide the numbers:

\frac{6}{3} = 2

= \frac{x ^{2}}{3} - 2 x + \frac{8}{3}

\frac{2 ( 6 - x ^{2} ) ^{2}}{x ^{2}}

2 π - 2 π x (2 - 2 x^{2})

\frac{2 - 2 x ^{2}}{( x ^{2} + 1 ) ^{2}}

(\frac{1}{3 x} + (- 3) x^{2})^{8}

\frac{1}{x ( x - a )}

What is expand ((x-2)(x-4))/3 ?
The solution to expand ((x-2)(x-4))/3 is (x^2)/3-2x+8/3