What is expand (2i,-3j)(1i,1j) ?

The solution to expand (2i,-3j)(1i,1j) is 2i(1*1i,j),-3j(1*1i,j)

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expand (2i,-3j)(1i,1j)

expand

(2 i, - 3 j) (1 i, 1 j)

2 i (1 \cdot 1 i, j), - 3 j (1 \cdot 1 i, j)

Solution steps

(2 i, - 3 j) (1 i, 1 \cdot j)

= (2 i, - 3 j) (1 \cdot 1 i, j)

Apply the distributive law:

a (b - c) = ab - a c

a = (1 i, 1 \cdot j), b = 2 i,, c = 3 j

= (1 i, 1 \cdot j) \cdot 2 i, - (1 i, 1 \cdot j) \cdot 3 j

= 2 i (1 \cdot 1 i, j), - 3 j (1 \cdot 1 i, j)

2 (x + d x)^{2}

(1 - 2 i) (1 + 2 i)

\frac{s + 5}{( s + 1 ) ( s + 4 )}

(e^{t} cos (t) - e^{t} sin (t)) (2 e^{t} cos (t))

(a - bi)^{2}

What is expand (2i,-3j)(1i,1j) ?
The solution to expand (2i,-3j)(1i,1j) is 2i(1*1i,j),-3j(1*1i,j)